![]() There's no good way to alter a list's length while iterating over it. Well organized and easy to understand Web building tutorials with lots of examples of how to use HTML, CSS, JavaScript, SQL, Python, PHP, Bootstrap, Java. ![]() 2.The time complexity of the lambda function is constant, O (1), since it only performs a single arithmetic operation. The time complexity of the filter function is O (n), where n is the number of elements in the list. That's the state of the list initially then 1 is removed and the loop goes to the second item in the list: 1.The filter function is used to filter the list of numbers, and it applies the lambda function to each element of the list. Nearby Search and Text Search allow additional parameters to filter. Perhaps it's easier to visualize like so, with a ^ pointing to the value of i: A Place Search returns a list of places along with summary information about each. List comprehension works: list3 x for x in list1 if x 'fruit' not in y. But as they're dictionaries with key-values that we want to ignore, you need to do it manually. ![]() Then the for loop goes to the second item in the list, which is not 2, but 3! Then that's removed from the list, and then the for loop goes on to the third item in the list, which is now 5. If your lists only had the values of fruit in them, you could create sets out of them and do the difference using python's built in function: list1.difference (list2). That means that the first time through the loop, i = 1, so 1 is removed from the list. ![]() You're modifying the list while you iterate over it. ![]()
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